Kinetic Theory of Gases

The ideal gas law is written as ...

The value of the universal gas constant $R$ is ...

According to kinetic theory, the absolute temperature of a gas represents ...

At constant temperature, the product of a gas's pressure and volume is constant. This is ... law.

At constant pressure, a gas's volume is proportional to its absolute temperature. This is ... law.

Avogadro's number is the number of particles in one mole of a substance, namely ...

A gas at $2\text{atm}$ and $3\text{L}$ is compressed at constant temperature until its pressure is $6\text{atm}$. The final volume is ...

A gas of volume $2\text{L}$ at $300\text{K}$ is heated at constant pressure to $450\text{K}$. Its final volume is ...

At standard conditions (STP), the volume of $2\text{mol}$ of ideal gas is ...

The average kinetic energy of one gas molecule at $300\text{K}$ is ... ($k=1.38\times 10^{-23}\text{J/K}$)

A gas in a closed container is at $1.5\text{atm}$ and $300\text{K}$. If heated to $400\text{K}$ at constant volume, its pressure becomes ...

The relationship of pressure, volume, and temperature for a fixed amount of gas is given by ...

The rms speed of gas molecules increases when ...

The number of molecules in $0.5\text{mol}$ of gas is ... ($N_A=6.02\times 10^{23}{\text{mol}}^{-1}$)

An ideal gas initially at $1\text{atm}$, $2\text{L}$, and $300\text{K}$ is heated to $600\text{K}$ while its pressure becomes $2\text{atm}$. The final volume is ...

The internal energy of $2\text{mol}$ of monatomic gas at $300\text{K}$ is ... ($R=8.314\text{J/(mol}\text{K)}$)

The rms speed of oxygen molecules ($M=32\text{g/mol}$) at $300\text{K}$ is ... ($R=8.314\text{J/(mol}\text{K)}$)

The density of nitrogen gas ($M=28\text{g/mol}$) at $1\times 10^5\text{Pa}$ and $300\text{K}$ is ... ($R=8.314\text{J/(mol}\text{K)}$)

Gas in a closed tank is at $2\times 10^5\text{Pa}$ and $300\text{K}$. If heated to $360\text{K}$ at constant volume, its pressure becomes ...

The number of molecules per unit volume of gas at $1\times 10^5\text{Pa}$ and $300\text{K}$ is ... ($k=1.38\times 10^{-23}\text{J/K}$)